Commands tagged meminfo (3)

  • This will show the amount of physical RAM that is left unused by the system. Show Sample Output


    4
    grep '^MemFree:' /proc/meminfo | awk '{ mem=($2)/(1024) ; printf "%0.0f MB\n", mem }'
    dbbolton · 2010-06-30 18:33:29 3
  • sort is way slow by default. This tells sort to use a buffer equal to half of the available free memory. It also will use multiple process for the sort equal to the number of cpus on your machine (if greater than 1). For me, it is magnitudes faster. If you put this in your bash_profile or startup file, it will be set correctly when bash is started. sort -S1 --parallel=2 <(echo) &>/dev/null && alias sortfast='sort -S$(($(sed '\''/MemF/!d;s/[^0-9]*//g'\'' /proc/meminfo)/2048)) $([ `nproc` -gt 1 ]&&echo -n --parallel=`nproc`)' Alternative echo|sort -S10M --parallel=2 &>/dev/null && alias sortfast="command sort -S$(($(sed '/MemT/!d;s/[^0-9]*//g' /proc/meminfo)/1024-200)) --parallel=$(($(command grep -c ^proc /proc/cpuinfo)*2))" Show Sample Output


    3
    alias sortfast='sort -S$(($(sed '\''/MemF/!d;s/[^0-9]*//g'\'' /proc/meminfo)/2048)) $([ `nproc` -gt 1 ]&&echo -n --parallel=`nproc`)'
    AskApache · 2012-02-28 01:34:58 6

  • 1
    mem() { ps -C "$1" -O rss | awk '{ count ++; sum += $2 }; END {count --; print "Number of processes:\t",count; print "Mem. usage per process:\t",sum/1024/count, "MB"; print "Total memory usage:\t", sum/1024, "MB" ;};'; }
    mikhail · 2022-01-23 16:14:24 373

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